HOW TO CALCULATE BRICKS, CEMENT, AND SAND QUANTITY IN 9″ BRICK WALL?

1)  Quantity of Bricks

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Assume, we have

Brick Size = 9” x 4.5” x 4.5”

Thickness of Wall = 9”

Thickness of Mortar = 0.4”

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Therefore, brick size with mortar   

 

 = (9+0.4) x (4.5+0.4) x (4.5+0.4)  

  = 9.4 x 4.9 x 4.9

 

Now, Number of bricks = Volume of Brickwork / (Volume of 1 brick with mortar)

 

Also, volume of 1 Brick

 

= 9 x 4.5 x 4.5

 

 = 182.25 cubic inch

  We know 1 feet = 12 inches 

 Therefore,

 Volume of 1 brick (feet)

  = 182.25 / (12 * 12 *12)

  = 0.055 cubic feet

 

 Also,

 

   Volume of 1 brick with mortar

   = 9.4 x 4.9 x 4.9

   = 225.694 cubic inch

 

 (In feet) = 225.694 / (12 * 12 *12)

 

 Volume of 1 brick with mortar = 0.131 cubic feet

 

Now,

Volume of Brick

 = (Height x length x Width) of wall    

= 10 x 6 x 9/12

 = 45 cubic feet

  Therefore,

 Number of bricks

 = Volume of Brickwork / (Volume of 1 brick with mortar)

= 45 / 0.131

= 344 bricks

 

 Also,

there will wastage of brick,

let it consider to be = 10 % of brick wastage 

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Therefore,

Number of bricks

= 344 + (344 x 0.1)

= 378 bricks

2) Quantity of Cement

Quantity of Mortar = Quantity of Brickwork - Volume of Bricks

Firstly, Volume of Bricks = Volume of 1 brick x Number of bricks

Volume of Bricks

= 0.055 cubic feet x 378

= 20.79 cubic feet 

      

Therefore,

   Quantity of Mortar

          = Quantity of Brickwork - Volume of Bricks

       = 45 – 29.79

        = 24.21 cubic feet  

   Let Mix Ratio -> 1:6

  

      Dry Volume of Mortar

          = Wet Volume x 33 % of Volume

          = wet volume x (1 + 0.33)

           = 24.21 x 1.33 

            = 32.2 cubic feet 

 

      Quantity of Cement

     = [{Dry Volume of Mortar x cement Ratio} / (Sum of Ratio)

             = 32.2 x 1 / (1+5)

              = 5.37 cubic feet

 

     We know, the density Of Cement = 1440 kg/m³

       Also, 1 m³ = 35.29 Cubic Feet

      Therefore,

           Quantity of Cement (m³)

             = 5.37 / 35.29

            = 0.152 m³

Therefore,

Weight of Cement

             = 1440 x .0152

             = 218 kg

      Also, we know, in 1 bag of cement 

 

     = 50 kg of cement 

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 ∴,

       Number of Cement bags

                              = 218.98 / 50

                             = 4.38

           (approx.) = 5 bags 

3) Quantity Of Sand

  Ratio-> 1:5

 ∴, 

Quantity of sand

= Quantity of Cement x 5

=5.37 x 5

=26.85 Cubic Feet

 

 Also, 1 m³=35.29 Cubic Feet

∴,

Quantity of Sand

= 26.85 / 35.29

= 0.760 m³

We know, Density of sand

= 1600 kg/m³

∴, 

Weight of Sand

                  = 0.76 x 1600

                   = 1271 kg 

          In Tonnes = 1.271 Tonnes 

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